In a quadrilateral abcd, angle a + angle d = 90°. prove that ac^2 + bd^2 = bc^2 + ad^2

Hence prove.

Step-by-step explanation:

Given:

∠A + ∠D = 90°

We are prove to that

Solution:

See required figure in attached file.

We know sum of the all angles of a triangle is 180°.

So, in triangle AED.

∠A + ∠E + ∠D = 180°

∠E + (∠A + ∠D) = 180°

Now, we substitute ∠A + ∠D = 90° in above equation.

∠E + 90° = 180°

∠E = 180° - 90°

∠E = 90°

Using Pythagoras Theorem for triangle ADE and triangle BEC.

Now, we add both above equations.

--------(1)

Similarly, Using Pythagoras Theorem for triangle AEC and triangle BED.

Now, we add both above equations.

--------(2)

We get From equation 1 and equation 2.

Hence prove,

hit or miss i guess they never miss huh

step-by-step explanation:

you got a boyfriend i bet he doesnt kiss ya

the height of the surface increases from the center out to the sides of the road.

step-by-step explanation:

as we move out we move away from the x-axis.

and as mentioned in the problem statement that height of a road increases when we move away from the center x.

hence proved that 3rd option

the height of the surface increases from the center out to the sides of the road.

is the correct option.