You are driving on an asphalt road that had a 40 mi/h speed limit. a bicyclist veered into your lane so you slam on your brakes. your tires left three skid marks of 69 ft, 70 ft, and 74 ft. the road had a drag factor of 0.95. your brakes were operating at 98% efficiency. the police gave you a ticket for speeding. you insist that you were driving under the speed limit. who is correct?

Policeman is correct.

Step-by-step explanation:

Consider the provided information.

The tires left three skid marks of 69 ft, 70 ft, and 74 ft.

The road had a drag factor of 0.95. Your brakes were operating at 98% efficiency.

Thus, drag factor (f) = 0.95 and brakes efficiency (n) = 0.98

Compute the skid distance by finding the mean of length of 3 skids.

Therefore, the skid distance is 71 ft.

Now find the speed of car using skid speed formula:

Where, S is the speed of car, D is the skid distance, f is the drag factor and n is the beak efficiency.

Substitute the respective values in above formula.

Your speed was 44.5312 mi/h which is greater than 40 mi/hr.  So policeman is correct.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

6e14 is the answer.