You have a triangle that has an altitude 5 inches longer than the base. if the area of your triangle is 63 square inches, what are the dimensions of the base and altitude?

Base of triangle is 9 inches and altitude of triangle is 14 inches.

Step-by-step explanation:

Given:

Area of Triangle = 63 sq. in.

Let base of the triangle be 'b'.

Let altitude of triangle be 'a'.

Now according to question;

altitude is 5 inches longer than the base.

hence equation can be framed as;

Now we know that Area of triangle is half times base and altitude.

Hence we get;

Substituting the values we get;

Now finding the roots for given equation we get;

Hence there are 2 values of b

Since base of triangle cannot be negative hence we can say

So Base of triangle = 9 inches.

Altitude = 5 + base  = 5 + 9 = 14 in.

Hence Base of triangle is 9 inches and altitude of triangle is 14 inches.

bn,mn,n.vn.

step-by-step explanation:

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x