Mathematics, 21.12.2019 04:31 robert7248
Ajob shop consists of three machines and two repairmen. the amount of time a machine works before breaking down is exponentially distributed with mean 10. if the amount of time it takes a single repairman to fix a machine is exponentially distributed with mean 8, then(a) what is the average number of machines not in use? (b) what proportion of time are both repairmen busy?
Answers: 2
![\sum\limits^3_{i=0} {P_i=1}\\\\p_0=[1+\frac{5}{12}+\frac{48}{25}+\frac{192}{250}]^{-1}=\frac{250}{1522}](/tpl/images/0428/6710/4aeab.png)
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Ajob shop consists of three machines and two repairmen. the amount of time a machine works before br...
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