In the diagram, which must be true for point p to be the centroid of the triangle? ln ⊥ jk, jo ⊥ lk, and jl ⊥ mk. jl = lk = kj jm = ml, lo = ok, and kn = nj. ln is a perpendicular bisector of jk, jo is a perpendicular bisector of lk, and mk is a perpendicular bisector of jl.

cheater

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

mnkjn

step-by-step explanation:

19

step-by-step explanation: