The circle below is centered at the point (4.1) and has a radius of length 2.what is its equation?

Hence the required equation of circle is

(x - 4)² + ( y - 1)² = 4

Step-by-step explanation:

The equation of a circle whose center (h, k) and radius r is given-

(x - h)² + (y - k)² = r²

Here given that-

Center = ( 4, 1) & r = 2

Equation of circle-

( x - 4)² + ( y - 1)² = 2²

(x - 4)² + ( y - 1)² = 4

x² + 16 - 8 x + y² + 1 - 2 y = 4

x² + y² -8 x - 2 y + 13 = 0

Hence the required equation of circle is

(x - 4)² + ( y - 1)² = 4

         0R

x² + y² - 8 x - 2 y + 13 = 0

there is no image or shapes attacted

step-by-step explanation:

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632