What is the solution to both systems a and b?
two systems of equations are shown. the first equation in
system b is the original equation in system a. the second
equation in system b is the sum of that equation and a
multiple of the second equation in system a.
(3, 4)
(3,5)
(4,3)
0 (5,3)
a
x+3y=11+x+3y=11
5x=y=17 - 15x-3y=51
15 7 / 8x = 62
b. x+3y=11
15 7 8 x = 52

he will have 300 because he is really broke and 300 is in his imangine

step-by-step explanation: he ehe heh step by the thy

10 - 75

step-by-step explanation:

there's nothing attached so it's most likely anything in that range.

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).