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Mathematics, 25.08.2019 05:30 roderickhinton

Solve for x: |x βˆ’ 2| + 10 = 12
x = 0 and x = 4
x = βˆ’4 and x = 0
x = βˆ’20 and x = 4
no solution

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Solve for x: |x βˆ’ 2| + 10 = 12
x = 0 and x = 4
x = βˆ’4 and x = 0
x = βˆ’20 and x = 4...
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