Triangle j'k'l' shown on grid below is a dilation of triangle jkl using the origin as the center of dilation; what is the scale factor used to create triangle j'k'l' ?

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

step-by-step explanation:

given expression is .

now we need to simplify the given expression .

we know that square root is equivalent to the power 1/2. so that means we can take half of the exponents to get the square root of given expression.

expanding that will give a very very large number so let's keep answer in exponent form.