Awebsite offers a coupon such that each customer has a

15

%

15%15, percent chance of getting the coupon each day they visit the site. aya visits the website for

6

66 consecutive days.

what is the probability that at aya will be offered a coupon on at least one of the days she visits the website?

round your answer to the nearest hundredth

0.62

Step-by-step explanation:

Let's call

A: Aya gets a coupon one day. P(A) = 0.15

B: Aya doesn't get a coupon one day. P(B) = 1 - 0.15 = 0.85

Aya doesn't get a coupon in any of 6 days  = P(B)^6 = 0.85^6 = 0.38

The probability of Aya getting at least 1 coupon after 6 days is the complement of don't getting any coupon after 6 days, that is:

1 - P(B)^6 =  1 - 0.38 = 0.62

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5