12. the equation for line g is given by
5y = -2x - 20. suppose line g is parallel to line r, and line e is perpendicular to line g. point (-10,8) lies on both line r and line e.
part a: write an equation in slope-
intercept form for line r.
part b: write an equation in slope-
intercept form for line e.

Step-by-step explanation:

line G :

5y = -2x - 20...put in slope intercept form (y = mx + b)

y = -2/5x - 4the slope(m) = -2/5

Part A.) slope intercept form for line R...since R is parallel to G, it will have the same slopeso slope(m) = -2/5

(-10,8)...x = -10 and y = 8

slope(m) = -2/5

y = mx + b

8 = -2/5(-10) + b

8 = 4 + b

8 - 4 = b

4 = b

so ur equation is : y = -2/5x + 4 <=== part A answer

since line E is perpendicular to line G, it will have a negative reciprocal slope...all that means is flip the slope and change the signso the slope of line E is : (flip -2/5-5/2change the sign5/2)

(-10,8)...x = -10 and y = 8

slope(m) = 5/2

y = mx + b

8 = 5/2(-10) + b

8 = -25 + b

8 + 25 = b

33 = b

so ur equation is : y = 5/2x + 33 <== part B answer

ur mom

step-by-step explanation: