Determine the point that lies on the equation y = -5x - 3.
(4, 12)
(4, -12)
(4, 23)
(4, -23)

(4, -23)

Step-by-step explanation:

To see if a point is on the equation, substitute its "x" and "y" coordinates into the equation. The points are written as (x, y). If the left side equals the right side, the point is on the line. (LS = RS)

Try (4, 12)

y = -5x - 3

12 = -5(4) - 3

12 = -20 - 3

12 = -23

LS ≠ RS

The point is not on the line.

Try (4, -12)

y = -5x - 3

-12 = -5(4) - 3

-12 = -20 - 3

-12 = -23

LS ≠ RS

The point is not on the line.

Try (4, 23)

y = -5x - 3

23 = -5(4) - 3

23 = -20 - 3

23 = -23

LS ≠ RS

The point is not on the line.

Try (4, -23)

y = -5x - 3

-23 = -5(4) - 3

-23 = -20 - 3

-23 = -23

LS = RS

The point (4, -23) is on the line.

question:

could we have options?

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3