Suppose that (n, e) is an rsa encryption key, with n = pq, where p and q are large primes and gcd(e, (p − 1)(q − 1)) = 1. furthermore, suppose that d is an inverse of e modulo (p − 1)(q − 1). suppose that c ≡ me (mod pq). in the text we showed that rsa decryption, that is, the congruence cd ≡ m (mod pq) holds when gcd(m, pq) = 1. show that this decryption congruence also holds when gcd(m, pq) > 1. [hint: use congruences modulo p and modulo q and apply the chinese remainder theorem.]

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

one fourth of 9% = 2.25%

gavin is correct in saying : the equivalent quarterly interest rate would be

2.25%.

10+4√2 is the answer. i dont have the time to explain.

the answer is that it is true