Afreight train made a trip to a repair. on the trip there it travelers 25 mph and on the return trip it went 20 mph. how long did there take if the return trip took 15 hours?

Time taken by train in onward journey = 12 hours.

Step-by-step explanation:

Given:

Speed of train making a trip to a repair = 25 mph

Speed of train on return trip = 20 mph

Time taken for return trip = 15 hours

To find the time taken on the on wards trip.

Solution:

The distance traveled by the train on the trip and return trip is the same as the y are of same trips in opposite directions.

Distance can be calculated by using the data for the return trip.

Distance=

Distance=

Speed of train for on ward trip = 25 mph

Time taken =

Time taken =

Thus, time taken by train in onward journey = 12 hours.

5x + 5

step-by-step explanation:

you should always add the diagrams and graphs we cannot see. this particular question is kind of borderline because we can make a graph for you.

(f + g)x = -x^2 +3x + 5 + x^2 + 2x

(f + g)x = 5x + 5

the graph of z = 5x + 5 is shown below. always use desmos when in doubt.