Consider two machines that are maintained by a single repairman. machine i functions for an exponentially distributed amount of time with rate λi before it fails. the repair times for each unit are exponential with rate µi . they are repaired in the order in which they fail. a. formulate a markov chain model for this situation with state space {0, 1, 2, 12, 21}. b. suppose that λ1 = 1, µ1 = 2, λ2 = 3, µ2 = 4. find the stationary distribution.

answer: b.

step-by-step explanation:

it is b. cause the equations are put in the right category

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870