Acontractor is considering a project that promises a profit of $46,000 with a probability of 0.7, or a loss (due to bad weather, strikes, and such) of $12,000 with a probability of 0.3.
if many projects have these same probabilities and costs, how much should the contractor expect to earn on average per contract?

$28,600

Step-by-step explanation:

Probably of 0.7 = 46000

Probability of 0.3 = 12000

The average profit = Sum of (x*Pr(x)

=0.7(46000) + 0.3(-12000)

= 32200 - 3600

= $28,600

The contractor should expect to earn $28,600 on the average

3432532

step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this