Mathematics, 18.12.2019 10:31 formulabmath

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let us consider a rather routine problem of laying a brick patio.

english system vs. metric system

problem: how many bricks 3.75 in. wide x 8 in. long problem: how many bricks 9.5 cm wide x 20 cm long
are required to cover a patio 16 ft. 3 in. wide are required to cover a patio 5 meters wide
by 19 ft. 8 in. long? by 6 meters long?

step 1. first, find the total width and length of the step 1. first, find the area of the patio in square cm.
patio in inches.
step 1a. convert the width and length in meters to cm:
step 1a. convert the portion of width and length width: 5 m = 5 x
a0 =
a1 cm
that is expressed in feet to inches: length: 6 m = 6 x
a2 =
a3 cm
width: 16 ft. = 16 x
a4 =
a5 in.
length: 19 ft. = 19 x
a6 =
a7 in. step 1b. find the area of the patio in square cm
by multiplying its width by its length:
step 1b. add these values to the portion of the width
a8 cm x
a9 cm =
a10 cm²
and length of the patio expressed in inches
to find totals:
total width:
a11 in. + 3 in. =
a12 in. step 2. find the area of each brick in square cm
total length:
a13 in. + 8 in. =
a14 in. by multiplying its width by its length:

a15 cm x
a16 cm =
a17 cm²
step 2. find the area of the patio in square inches by
multiplying its total width by its total length: step 3. find the number of bricks needed by dividing

a18 in. x
a19 in. =
a20 in.² the patio area by the brick area (round up to
the nearest whole brick):
step 3. find the area of each brick in square inches
a21/
a22 =
a23 bricks
by multiplying its width by its length:

a24 in. x
a25 in. =
a26 in.²

step 4. find the number of bricks needed by dividing
the patio area by the brick area (round up to
the nearest whole brick):

a27/
a28 =
a29 bricks

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