One number is 4 less than 3 times the second number. if t3 more than two times the first number is decreased by two times the second, the result is 11. what are both numbers?

4 and 0

Step-by-step explanation:

Let one number be x

Let second number be y

One number = 4-3y

(3+2x)-2y=11

Substitutue one number x in the equation

(3+2(4-3y)) -2y=11

Open inner bracket

(3+8-6y) -2y=11

Open the final bracket

3+8-6y-2y=11

11-8y=11

-8y=11-11

-8y=0

y=0 ( this is because zero cant be divided)

One number = 4-3y

Substitute y

4-3(0)

4-0=4

x=4

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

idk

step-by-step explanation: