Write an equation of the parabola in intercept form  that  passes through  (0,  −18) with  x-intercepts of  9  and  1

an equation of the parabola is  y=

y=-2(x-9)(x-1)

Step-by-step explanation:

y=a(x-r)(x-s)

y=a(x-9)(x-1)

-18=a(0-9)(0-1)

-18=a(-9)(-1)

-18=a(9)

-18=9a

a=-18/9

a=-2

y=-2(x-9)(x-1)

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step-by-step explanation:

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step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2