Suppose δabc has an exterior angle at vertex b. the exterior angle is (12x−24)º, m∠a=(3x−6)°, and m∠c=(6x+12)°. what is the measure of the exterior angle at vertex b?

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !