The angle of elevation from a soccer ball on the ground to the top of the goal is 34°. if the
goal is 8 feet tall, what is the distance from the ball to the goal?

11.9 feet (3 s.f.)

Step-by-step explanation:

Let the distance from the ball to the goal be FB feet.

tan 34°= GF/FB

tan 34°= 8/FB

FB (tan34°)= 8

FB= 8/tan 34°

FB= 11.860 (5s.f.)

Therefore, distance from the ball to the goal is 11.9 feet (3 s.f.)

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step-by-step explanation: