7- -3(x+3)> 5 how do i work this problem

x > 1

Step-by-step explanation:

It's actually a pretty simple algebra problem, you can pretend the > is an = for the most part.  The only difference is if you ever multiply or divide by a negative you flip the direction

-7 + 3(x+3)>5 (as long as that double minus sign was accurate)

-7 + 3x + 9 > 5

2 + 3x >5

3x > 3

x > 1

Now, like I mentioned if you divide or multiply by a negative the inequality flips.  so say you multiply by -1 on both sides you will get -x < -2.  I just want to make sure you remember that because it can be hard to remember.

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

step-by-step explanation: