Guest ages at a ski mountain resort typically have a right-skewed distribution. assume the standard deviation (σ) of age is 14.5 years. from a random sample of 40 guests the sample mean is 36.4 years. calculate a 99 percent confidence interval for µ, the true mean age of guests.

(30.49 years, 42.31 years)

Step-by-step explanation:

The formula to find the confidence interval is given by :-

, where = Sample mean

z* = Critical value.

= Population standard deviation.

n= Sample size.

As per given , we have

n= 40

We know that the critical value for 99% confidence interval : z* = 2.576 (By z-table)

A 99 percent confidence interval for µ, the true mean age of guests will be :

∴ a 99 percent confidence interval for µ, the true mean age of guests  = (30.49 years, 42.31 years)

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

b and c

step-by-step explanation: