1)what is the mass of nitrogen in nh3? (use two decimal places)

2)what is the total mass of hydrogen in nh3? (use two decimal places)

3)what is the molar mass of nh3? (use 2 decimal places)

1)  The Mass of Nitrogen in is 14.00 gm.

2) The Mass of Hydrogen in is 3.00 gm.

3)The Molar Mass of is 17.00 gm.

Step-by-step explanation:

Solving for Part 1.

In that is Ammonia there is 1 atom of Nitrogen.

So the atomic mass of Nitrogen is same as the mass of Nitrogen in .

Atomic mass of Nitrogen = 14.00 gm

Hence The Mass of Nitrogen in is 14.00 gm.

Solving for Part 2.

In  there are 3 atoms of Hydrogen.

Atomic mass of Hydrogen = 1.00 gm

So the mass of Hydrogen in   is 3 times of its atomic mass.

Mass of Hydrogen = 3 × Atomic mass of Hydrogen

Hence The Mass of Hydrogen in is 3.00 gm.

Solving for Part 3.

In  there is 1 atom Nitrogen and 3 atoms of Hydrogen.

So molar mass is the sum of mass of nitrogen and mass of Hydrogen in .

Molar mass of =Mass of Nitrogen+Mass of Hydrogen

Hence The Molar Mass of is 17.00 gm.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.