If a parabola opens downwards and has a maximum, and if it has a vertex of (-2,-3) and a y-intercept of (0,-11), what is the axis of symmetry, and what is the maximum value of the function?

Its maximum value is -3 and its axis of symmetry is x = -2.

Step-by-step explanation:

We can write it in vertex form:

y = a(x + 2)^2  - 3  where a is a constant.

When x = 0 y = -11 (the y-intercept), so:

-11 = a(0 + 2)^2 - 3

-11 = 4a - 3

4a = -8

a = -2

So the equation of the parabola is

y = -2(x + 3)^2 - 3.

Its maximum value is -3 and its axis of symmetry is x = -2.

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

15 units use socratic

step-by-step explanation: 15 units