![\dfrac{\sqrt{2}}{\sqrt[3]{2}}=2^{1/2-1/3}=2^{1/6}](/tpl/images/0420/0215/b15d6.png)
Simplify β2/3β2 (it's asking for an easier way to solve this) i think it's 2 3/2
2 to th...
Mathematics, 16.12.2019 01:31 1lilzomb
Simplify β2/3β2 (it's asking for an easier way to solve this) i think it's 2 3/2
2 to the power of one sixth
2 to the power of one third
2 to the power of five sixths
2 to the power of three halves
Answers: 1
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