Find the values of a & b so that x^4+x^3+ax+b is divisible by x^2+1

a = 1 b = -1.

Step-by-step explanation:

Suppose the quotient when you divide x^4+x^3+ax+b  by x^2 + 1 is

x^2 + ax + b then expanding we have:

(x^2 + 1)(x^2 + ax + b)

= x^4 + ax^3 + bx^2 + x^2 + ax + b

= x^4 + ax^3 + (b + 1)x^2 + ax + b Comparing this with the original expression:

  x^4 +  x^3  + 0 x^2       + ax + b  Comparing coefficients:

a = 1 and b+ 1 = 0 so b = -1.

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: