To estimate the height of a stone figure, anya holds a small square up to her eyes and walks backwards from the figure. she stops when the bottom of the figure aligns with the bottom edge of the square and the top of the figure aligns with the top edge of the square. her eye level is 1.84 m from the ground. she is 3.50 m from the figure. what is the height of the figure to the nearest hundredth of a meter?

a.8.50 m

b.4.38 m

c.6.65 m

d.2.45 m

8.50 m is the height of the figure to the nearest hundredth of a meter.

Option A

Step-by-step explanation:

So from the figure we have,

Angle CBA = Angle DBA  = 90 degree

Angle CAB = Angle ADB  = 90 degree

Angle CAB = Angle BDA = 90 degree

Now using the similar triangle properties and Pythagorean theorem,

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol