Triangle abc and def are similar. find the lengths of ab and ef

Step-by-step explanation:

Though the figures were not clear enough. Going by the conditions for similar triangles, AB/DE = BC/EF.

since AB = 5x, BC = 4, DE = 5, EF = x from the figures I managed to see, it implies that AB/DE =BC/EF;

5x/5 = 4/x, when you cross multiply,

5x X x = 5 X 4; 5x² = 20. Divide through by 5, it now becomes, x² = 4

Therefore, taking the square root of both side √x² = +- √4, x = +-2. So since AB = 5x , AB now =5x2 = 10, and EF = x = 2.

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