Jessica traveled to portland by car. going there took 3 hours, and the return trip lasted 6 hours. jessica averaged a speed of 43mph while returning. find the average speed of the trip there

The average speed of the trip there is 86 mph.

Step-by-step explanation:

Given:

Time taken to reach Portland = 3 hours

Time taken to come beck from Portland = 6 hours

Average speed for the returning trip = 43 mph

Distance traveled for the returning trip can be obtained by multiplying the returning speed by returning time. Therefore, distance for returning trip is:

Now, distance traveled for the return trip is same as going to the trip.

So, distance traveled by Jessica going to Portland = 258 miles.

Time taken to go there = 3 hours

Therefore, speed of the trip there is given as the ratio of distance and time and is given as:

Therefore, the average speed of Jessica's car to go to Portland is 86 mph.

she was supposed to add the hours(38.5) and multiply the amount of money she earned(7.50) resulting in $288.75 .

correct me if i'm wrong and if it is i'm truly sorry.

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb