Abolt falls off an airplane at an altitude of 500 m. how long will it take the bolt to reach
the ground?

t = sqrt(500/4.9) =~ 10.1 seconds/ 10.1015 seconds (this is approximate)

Step-by-step explanation:

Use 4.9t^2 + v0t = s

a) A bolt falls off an airplane at an altitude of 500 m. Approximately how long does it take the bolt to reach the ground?

s = 4.9t^2 + v0t = 500

4.9t^2 = 500

t = sqrt(500/4.9) =~ 10.1 seconds

Part A)

v = initial velocity = 0

s = 500 = vertical distance the object travels (from plane to ground)  

Plug in the given values and solve for t

4.9t^2 + v*t = s

4.9t^2 + 0*t = 500

4.9t^2 + 0 = 500

4.9t^2 = 500

t^2 = 500/4.9

t^2 = 102.04081632653

t = sqrt(102.04081632653)

t = 10.101525445522

t = 10.1015

10.1015 seconds (this is approximate)

answer: b.

step-by-step explanation:

the y coordinate for point b is 0, and answer b is the only one with that y coordinate.