Abag contains 8 red marbles, 6 blue marbles and 2 green marbles. if two marbles are
drawn out of the bag, what is the probability, to the nearest 10th of a percent, that
both marbles drawn will be blue?

There are 16 total marbles with 6 blue ones.

Picking a blue one first is 6/16,  reduces to 3/8

After picking a blue one first there are 5 blue ones left and 15 total marbles, so picking another blue would be 5/15, reduces to 1/3

The probability of picking both blue, multiply the two together:

3/8 x 1/3 = 3/24 = 1/8 = 0.125 x 100 = 12.5%

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6