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Mathematics, 13.12.2019 17:31 badpotterchris

According to a cbs news poll, 73% of the 321 randomly selected adults aged 18-30 favor allowing gay and lesbian couples to marry legally compared to 53% of the 562 randomly selected adults of all ages that favor such legalization, a difference of 20%. to compute the likelihood that you'd see such a difference or more just due to the luck of the draw, you first need to calculate the se of the 2 samples.

a. in the young adult poll 73% favored gay marriage. calculate the se for this percentage. round your answer to 2 decimal places.
b. in the all adult poll 53% favored gay marriage. calculate the se for this percentage.
c. the difference is 20%. calculate the se for this difference.
d. what is the value of the test statistic z?
e. what is the p-value?
f. should you reject the null hypothesis, that the difference is due to chance?
i. yes, doesn't look like the difference could be due to chance.
ii. no, it looks like the difference could easily be explained by chance.

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