Mark has one blue dress shirt, one white dress shirt, one black dress shirt, one pair of black slacks, one pair of grey slacks, and one red tie. all six of his possible outfits are listed below. let a aa be the event that mark's little brother selects an outfit with a white shirt and grey slacks and b bb be the event that he selects an outfit with a black shirt. what is p ( a or b ) p(a or b)p, left parenthesis, a, start text, space, o, r, space, end text, b, right parenthesis, the probability that mark's little brother selects an outfit with a white shirt and grey slacks or an outfit with a black shirt?

Mark's little brother selects an outfit with a white shirt and grey slacks or an outfit with a black shirt then the probability is 2/3

Step-by-step explanation:

Shirt : 3 choices

slacks : 2 choice

pick a tie : 1 time

So combinations : 3 *2 *1 = 6

3 outfit with gray slacks from 6 = 3 / 6 = 1/2

2 outfit with white shirt from 6 = 2/6 = 1/3

for the selection of white shirt and gray slacks is simply add both probability and subtract the probability of white shirt and grey slack which is

1/2 + 1/3 - 1/6

3/6 + 2/6 - 1/6 = 4/6 = 2/3

-The subset consists of all the outfits that do not have a white shirt.

-The subset consists of all the outfits that have either a blue shirt or a black shirt.

Step-by-step explanation:

answer: b.36 feet

step-by-step explanation:

96 39 cause 135 -96=39 im smart (i used a calculater)