Na city, 49% of the adults are male. 24% of the adults are male and rent action-movie dvds, and 10% of the adults are female and rent action-movie dvds. if an adult is randomly selected for a survey, what is the probability that the adult rents action-movie dvds, given that the adult is female?

Let's assume that since 49% of the adults in the city are males, then the rest of the population (which is 51%) are females. This means that 51 adults out of 100 (hypothetically) are females. Since the percentage of adult females who rent action-movie DVDs is 10% and there are 51 females in the city, then it should come at a ratio of 10/51. 

Thus, the answer is that the probability of an adult female who rents action-movie DVD getting picked in the sample is .1961 or .20 (that's 20%) of the whole population in the city.

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.

At a constant it will take one hour to travel 32 mi.at that speed it will take 1/2 hr to travel the remaining 16 mi.it will take 1+1/2 hr to travel the 48mi @ 32mph.so 1 hr = 60 min& 1/2 hr = 30 min1+1/2 hr = 90 min.there are 60s in each 90 × 60 = 3600 seconds.the real question seriously is he why are they driving so slow? ! lol.