The sum of three numbers is 108. the second number is 4 times the third. the first number is 6 more than the third. what are the numbers?

The numbers are 23, 68 and 17.

Step-by-step explanation:

Given:

The sum of three numbers is 108.

The second number is 4 times the third.

The first number is 6 more than the third.

Now, to find the numbers.

Let the third number be .

The second number be .

And the first number be .

According to question:

Now adding the variables we get:

⇒

Subtracting both sides by 6 we get:

⇒

Dividing both sides by 6 we get:

⇒

Third number =  

Second number =  

First number =

Therefore, the numbers are 23, 68 and 17.

4.08%

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°