The gravitational force of attraction between two students sitting at their desks in physics class is 3.20 x 10-18 n. if one student has a mass of 50.0 kg and the other has a mass of 60.0 kg, how far apart are the students sitting?

r  =  25*10⁴ m     [please read note]

Step-by-step explanation:

Newton´s law of gravitational force of attraction is:

F  = [ G   m₁ *m₂ ] / r²     (1)

From that equation we know:

G = 6.67 * 10⁻¹¹ [N*m²/kg² ]

F  = 3.20 *10⁻¹⁸ N

Two bodies

 m₁  =  50 kg

 m₂  =  60 kg

question is how far away they are.

By subtitution in equation (1)

3.20*10⁻¹⁸ (N) = {  6.67 * 10⁻¹¹ [N*m²/kg² ] *  50 [kg]*60[ kg] } / r²

3.20*10⁻¹⁸ = 20010 * 10⁻¹¹[  m²] / r²

r²   =  20010/3.20*10⁷ m²

r²   =  6253* 10⁷ m²

r²    =  625,3*10⁸ m²

r  =  25*10⁴ m

Note:

Then I  after looking similar problems in google I conclude there must be an error in problem statement  the result  25*10⁴ is certanly too big for a class room. Maybe F  is 3.20 * 10⁻⁸ then we get  d = 6 mt

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)

is this part of a question or something