What is the equation for a line passing through (-2,3) and perpendicular to y= -1/2+1 ?

Step-by-step explanation:

The correct question is

what is the equation for a line passing through (-2,3) and perpendicular to y= -1/2x+1 ?

Remember

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes are equal to -1)

The slope of the given line is m=-1/2

so

the opposite reciprocal is m=2

Find the equation of the line in point slope form

we have

substitute

Convert to slope intercept form

isolate the variable y

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )