What are the roots of the equation x^2+6x-9=10?

-3+2sqrt7

-3-2sqrt7

Step-by-step explanation:

x^2+6x-9=10

x^2+6x-9-10=0

x^2+6x-19=0

ax^2+bx+c=0

a=1 b=6 c=-19

As cannot be solved by completing square we will use quadratic equation

x= (-b+sqrt(b^2-4ac))/2a     and      x= (-b-sqrt(b^2-4ac))/2a

x= (-6+sqrt(6^2-4*-19))/2     and      x= (-6-sqrt(6^2-4*-19))/2

x=(-6+sqrt(36+76))/2           and      x=(-6-sqrt(36+76))/2

x=(-6+4sqrt7)/2                   and       x=(-6-4sqrt7)/2

x=(-3+2sqrt7)                       and      x=(-3-2sqrt7)

x=2.29                                 and      x= -8.29

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere

srry idk

step-by-step explanation: