The length of one base of a trapezoid is 19 inches and the length of the midsegment is 16 inches. find the length of the other base.

The Length of other side of Trapezoid is 13 inches

Step-by-step explanation:

Given as :

The length of the one base of trapezoid = L = 19 inches

The length of the mid segment = M = 16 inches

Let The length of other side = L' inches

Now, From trapezoid formula

The length of mid segment = × ( sum of opposite sides )

So, M =   × ( L + L' )

or, 16 inches = × ( 19 inches + L' )

Or, 16 inches × 2 = 19 inches + L'

Or, 32 inches = 19 inches + L'

∴ L' = 32 inches - 19 inches

I.e L' = 13 inches

So, measure of other side = L' = 13 inches

Hence, The Length of other side of Trapezoid is 13 inches Answer

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)