The annual interest on a $17,000 investment exceeds the interest earned on an $8000 investment by $276. the $17,000 is invested at a 0.3% higher rate of interest than the $8000. what is the interest rate of each investment?

your answer would be 10x - 1

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step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

150.6

all i did was i multiplied 5.02 by 30