48: 17
what is the general equation of a cosine function with an amplitude of 3, a period of 4x, and a horizontal shift of - ?
wost 4x+)
y = 4 *cos(3(x– 5))
y = 3cos(4x(x+5))
y = 3cos(0.5(x+x))
y - 4x00s(o 2(x+x))

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

i am sure it will be 90 degrees.

step-by-step explanation:

the difference between a number and 5 is -2.

step-by-step explanation:

notice that the equation you are given has -2 (negative 2) on the right side, not 2. when you subtract 5 from a number n, you are finding the difference between the number and 5.

the difference between a number and 5 is -2.