The rate of change of the population of a small town is dpdt=kp, where p is the population, t is time in years and k is the growth rate. if p=3 when t=3 and p=4 when t=5, what is the population when t=10? round your answer to the nearest integer.

P (10) = 65,000

Step-by-step explanation:

Change in population from t=3 to t =5  = 40,000-30,000 = 10,000

The rate of change of the population is given by:

Integrating the above function in the interval t =3 to t =5 gives us the change in population in the period.

This means that the population increases steadily by 5,000 people each year.

The population for t=10 is:

answer is x<

da freeck kinda math is this just drop out

step-by-step explanation: