Luiza is jumping on a trampoline. ht models her distance above the ground (in m) t seconds after she starts
jumping. here, t is entered in radians.
h(t) =-0.6 cos (2pi/2.5)t + 1.5
what is the second time when luiza reaches a height of 1.2 m?
round your final answer to the nearest hundredth of a second.

answer: ok

step-by-step explanation:

it would be 6xy and -16xy.

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)