Write an equation parallel to y=1/3x-7 that passes through the point (-2, 5)

The equation parallel to that passes through the point (-2, 5) is

Solution:

Given that line parallel to that passes through the point (-2, 5)

We have to find the equation of line

Let us first find the slope of line

The slope intercept form is given as:

y = mx + c  ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given equation of line is:

-------- eqn 2

On comparing eqn 1 and eqn 2,

Thus the slope of line "m" =

We know that slope of parallel lines are equal

So slope of line parallel to is also

Now let us find the equation of line with slope and passes through point (-2, 5)

Substitute "m" and (x, y) = (-2, 5) in eqn 1

15 = -2 + 3c

17 = 3c

So the required equation is:

Substitute "m" and "c" value in eqn 1

Thus the required equation is found

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step-by-step explanation:

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363