Onvert this system to a second order differential equation in yy by differentiating the second equation with respect to tt and substituting for xx from the first equation. solve the equation you obtained for yy as a function of tt; hence find xx as a function of tt. if we also require x(0)=4x(0)=4 and y(0)=5y(0)=5, what are xx and yy?

the first one

step-by-step explanation:

just id the test.

i have no idea just need points sorry

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)