The sum of three consecutive even integers is 108. what is the largest number?

a.34
b.35
c.37
d.38

The largest of three numbers  is 38.

Step-by-step explanation:

Given : The sum of three consecutive even integers is 108.

We have to find the largest of three consecutive even integer.

Consecutive integers are integer having a difference of one between each term . example 14 , 15, 16 ..

consecutive even integers are integers having a difference of two between them such that first term is in the form of 2n , where n is integers.

Consider the three consecutive even integers are 2n , 2n + 2 , 2n + 4

Also, given The sum of three consecutive even integers is 108.

that is 2n + 2n + 2 + 2n + 4 = 108

Simplify, we get,

6n + 6 = 108

Subtract 6 both side, we get,

6n = 102

Divide by 6 both side, we get,

n = 17

Thus, numbers are 2n = 2 × 17 = 34

2n + 2 = 34 + 2 = 36

2n + 4 = 34 + 4 = 38

Thus, The sum of three consecutive even integers is 108 then integers are 34, 36, 38 .

Thus, The largest of three numbers  is 38.

-14 is the answer

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