Aprofessor teaches a certain section of material using a lot of examples with sports and cars to illustrate. he is concerned that this may have biased his instruction to favor male students. to test this, he measures exam grades from this section of material among women ( n = 10) and men (n = 10). the mean score in the male group was 84 ± 4.0 (m ± sd); in the female group, it was 78 ± 8.0 (m ± sd) points. if the null hypothesis is that there is no difference in exam scores, then test the null hypothesis at a .05 level of significance for a two-tailed test.

There is difference in the scores of males and females

Step-by-step explanation:

Given that a professor teaches a certain section of material using a lot of examples with sports and cars to illustrate. He is concerned that this may have biased his instruction to favor male students

Since simple variances are unequal, we can do t test for comparison of two means with unequal variances

Group   Group One     Group Two  

Mean84.0078.00

SD4.008.00

SEM1.262.53

N10    10

The mean of Group One minus Group Two equals 6.00

 95% confidence interval of this difference: From 0.06 to 11.94

t = 2.1213

 df = 18

 standard error of difference = 2.828

The two-tailed P value equals 0.0480

Since p <0.05 we reject null hypothesis

There is difference in the scores of males and females

is there answer choices?

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.