In a mixture of good and silver 420 ounces of gold were required to make 907 mixture how much silver was required to make 2100 ounces of the mixture?

The amount of silver used in 2100 ounce mixture  is 972.44 ounce.

Step-by-step explanation:

The amount of silver used in 907 ounce mixture  = 420 ounce

⇒ The ratio of Silver Used : Total Mixture  =  420 : 907  ..  (1)

Let us assume the amount of silver used in 2100 ounce mixture  = m

⇒ The ratio of Silver Used : Total Mixture  =  m : 2100   .... (2)

Now, by the  RATIO OF PROPORTIONALITY:

As, both equation (1) and (2) represent the same ratio, so they should be equivalent.

⇒  420 : 907  =  m : 2100

or, m = 972.44 ounces

Hence, the amount of silver used in 2100 ounce mixture  is 972.44 ounce.

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)