Aerial’s grandmother gave her 5500 to save for her collage education. she went to the bank to open a savings account. the bank told her they had two options available.

account a will pay 5.5% simple interest
until the account is payed

account b i will pay 4.5% simple interest and if the account is left open for longer than 3 years, then at the end of the third year a bonus account will be opened with $250 that also earns 4.5% for the remainder of the time the initial account is open. when the initial account is closed, the bonus account will be closed as well as the money firm the two accounts will be combined.

if arial is planning on leaving the money in the account for 4 years and then withdrawing all funds, then the is the better choice earning her more.

Account B is the better choice for earning her (6751.25 - 6710) = $41.25 more.  

Step-by-step explanation:

Account A will pay 5.5% simple interest until the account is paid.

Therefore, after 4 years the principal $5500 will grow up to dollars.  

Now, Account B will pay 4.5% simple interest and if the account is left open for longer than 3 years, then at the end of the third year a bonus account will be opened with $250 that also earns 4.5% for the remainder of the time the initial account is open.

Therefore, after 4 years the principal $5500 will grow with a simple interest of 4.5% and the bonus $250 will earn the same rate of simple interest for 1 year.

Hence, the total sum will become dollars.

Therefore, account B is the better choice for earning her (6751.25 - 6710) = $41.25 more.  (Answer)

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

justin bieber ml.